Huh. Does that mean I can write class A { public: virtual void foo() = 0; }; voi... | Hacker News

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anon4 on June 28, 2015 | parent | context | favorite | on: C++'s Rule of Zero

Huh. Does that mean I can write

    class A {
    public:
    virtual void foo() = 0;
    };
    void A::foo() {}
    class B: public class A {};
    B b;
    b.foo();

and that will work?

pbsd on June 28, 2015 [–]

No, it will complain that A::foo is pure virtual, and that B must implement `foo`. However, if you define in B the method `void foo() { A::foo(); }`, it will work. In destructors this happens implicitly.

There was an old Herb Sutter GotW about this: http://www.gotw.ca/gotw/031.htm

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