UB doesn't exist in the processor (it does, but not here). *If the compiler know... | Hacker News

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		immibis 13 days ago \| parent \| context \| favorite \| on: You can't fool the optimizer UB doesn't exist in the processor (it does, but not here). If the compiler knows the pointer is aligned it can do the transformation.

zrm 11 days ago [–]

For the compiler to know the pointer is aligned it would have to actually be aligned and there is no guarantee that it is.

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