The first arg to your program is a path to the binary that's being executed. No ... | Hacker News

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		eptcyka on Jan 23, 2024 \| parent \| context \| favorite \| on: Self-contained Linux applications with lone Lisp The first arg to your program is a path to the binary that's being executed. No /proc required.

electroly on Jan 23, 2024 [–]

It's usually the path to the binary being executed, but you can pass anything you want when you exec. e.g. execl("/bin/ls", "definitely not /bin/ls", NULL);

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