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meisel
on Nov 30, 2023
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Herbie: Find and fix floating-point accuracy probl...
Why doesn't it make sense to use in that case?
bee_rider
on Nov 30, 2023
[–]
The dimensions of (A-UBU’) are the same as the dimensions of A. After you apply Woodbury, you have
inv(A) - (other stuff)
So, it only makes sense if A is much easier to solve than (A-UBU’).
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