> Rust will do a lot of invisible memory relocations under the covers.
I don't think it's quite accurate to point to "invisible memory relocations" as the problem that pinning solves. In most cases, memory relocations in Rust are very explicit, by moving an owned value when it has no live references (if it has any references, the borrow checker will stop you), or calling mem::replace() or mem::swap(), or something along those lines.
Instead, the primary purpose of pinning is to mark these explicit relocations as unsafe for certain objects (that are referenced elsewhere by raw pointer), so that external users must promise not to relocate certain objects on pain of causing UB with your interface. In C/C++, or indeed in unsafe Rust, the same idea can be more trivially indicated by a comment such as /* Don't mess with this object until such-and-such other code is done using it! */. All pinning does is to enforce this rule at compile time for all safe code.
I don't think it's quite accurate to point to "invisible memory relocations" as the problem that pinning solves. In most cases, memory relocations in Rust are very explicit, by moving an owned value when it has no live references (if it has any references, the borrow checker will stop you), or calling mem::replace() or mem::swap(), or something along those lines.
Instead, the primary purpose of pinning is to mark these explicit relocations as unsafe for certain objects (that are referenced elsewhere by raw pointer), so that external users must promise not to relocate certain objects on pain of causing UB with your interface. In C/C++, or indeed in unsafe Rust, the same idea can be more trivially indicated by a comment such as /* Don't mess with this object until such-and-such other code is done using it! */. All pinning does is to enforce this rule at compile time for all safe code.