Whenever your chip draws current from the power-rails in short bursts you esentially momentarily pull down the voltage of the power rail, and it can do that because the power supply has a non-zero internal resistance and thus forms a voltage divider with everything that is connected to it. This dip in voltage can affect neighbouring chips.
The solution is to install a small bucket/reservoir (a capacitor) which is filled with enough charge to serve that burst and smooth it's effect on the power rails (and thus decoupling it from the neighbouring components). The size of that capacitor depends on the load, but for most ICs it is enough to put one 100nF capacitor per power rail, but check the datasheet for more info.
The solution is to install a small bucket/reservoir (a capacitor) which is filled with enough charge to serve that burst and smooth it's effect on the power rails (and thus decoupling it from the neighbouring components). The size of that capacitor depends on the load, but for most ICs it is enough to put one 100nF capacitor per power rail, but check the datasheet for more info.