The main 'problem' there is the `global` keyword :^) (it's not needed for read access)

How would you read foo if it is hidden by a local parameter.

I guess not at all. It's shadowed. But this being Python, this is a way:

    foo = 123
    def lol(foo="bar"):
        print(globals()["foo"], foo)

That will output "123 bar". But it's terrible!

Your example is a SyntaxError, it doesn't even compile:

    In [1]: def myfunc(foo="bar"):
       ...:     global foo
      Input In [1]
        global foo
        ^
    SyntaxError: name 'foo' is parameter and global

> But this being Python, this is a way

That's why I said nonlocal or global ;)

Seems like you shouldn’t do that?