* Stars in the Milky Way: 400 Billion
* Galaxes in the universe: 2 Trillion
So (4x10^11)x(2x10^12)=8x10^23 stars in the universe.
* Size of IPv6 address space: 3.4x10^38
Find the ratio between addresses and stars:
* 3.4x10^38 / 8x10^23
IPv6 offers about 430 trillion times more addresses than estimated stars in the universe.
From Tom Coffee's presentation "An Enterprise IPv6 Address Planning Case-Study"
* https://www.youtube.com/watch?v=7Tnh4upTOC4
On the surface of the Earth, there are 8.4 IPv4 addresses per km^2. Not counting the oceans, that would be 28 IPv4 addresses per km^2 land.
IPv6 gives 10^17 addresses per mm^2 (yes, square millimeter).
In terms of volume, 10^8 IPv6 addresses per mm^3 throughout the Earth.
Not that it practically matters, but: is that the 'full surface' or not counting the oceans (land-only)?
* Stars in the Milky Way: 400 Billion
* Galaxes in the universe: 2 Trillion
So (4x10^11)x(2x10^12)=8x10^23 stars in the universe.
* Size of IPv6 address space: 3.4x10^38
Find the ratio between addresses and stars:
* 3.4x10^38 / 8x10^23
IPv6 offers about 430 trillion times more addresses than estimated stars in the universe.
From Tom Coffee's presentation "An Enterprise IPv6 Address Planning Case-Study"
* https://www.youtube.com/watch?v=7Tnh4upTOC4