Hacker News new | past | comments | ask | show | jobs | submit login

I was thinking about this since I read the article. The number you state seems to be 0.5% of total subjects. To my understanding, this is not how "p < 0.005" is employed.

If we take the control group, we have P(Corona)=90/15000. The likelyhood of getting as an extreme result in the vaccine group is then P(0 cases) + ... + P(5 cases) = [math and statistics] = the actual p-value.

How did you determine the statistical significance in your post?




Consider applying for YC's Fall 2025 batch! Applications are open till Aug 4

Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact

Search: