[1,2,3].map {|n| n*n }.reject {|n| n%3==1 } [1,2,3] |> Enum.map(&(&1*&1)) |> Enu...

fouc on Sept 11, 2020 | parent | context | favorite | on: Elixir Is Erlang, not Ruby

    [1,2,3].map {|n| n*n }.reject {|n| n%3==1 }

    [1,2,3] |> Enum.map(&(&1*&1)) |> Enum.reject(&(rem(&1,3)==1))

Still somewhat familiar heh